4y^2-4y+4=3

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Solution for 4y^2-4y+4=3 equation: 



4y^2-4y+4=3

We move all terms to the left:

4y^2-4y+4-(3)=0

We add all the numbers together, and all the variables

4y^2-4y+1=0

a = 4; b = -4; c = +1;
Δ = b2-4ac
Δ = -42-4·4·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{4}{8}=1/2$

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